12v^2-28v+16=0

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Solution for 12v^2-28v+16=0 equation:


Simplifying
12v2 + -28v + 16 = 0

Reorder the terms:
16 + -28v + 12v2 = 0

Solving
16 + -28v + 12v2 = 0

Solving for variable 'v'.

Factor out the Greatest Common Factor (GCF), '4'.
4(4 + -7v + 3v2) = 0

Factor a trinomial.
4((1 + -1v)(4 + -3v)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(1 + -1v)' equal to zero and attempt to solve: Simplifying 1 + -1v = 0 Solving 1 + -1v = 0 Move all terms containing v to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1v = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1v = 0 + -1 -1v = 0 + -1 Combine like terms: 0 + -1 = -1 -1v = -1 Divide each side by '-1'. v = 1 Simplifying v = 1

Subproblem 2

Set the factor '(4 + -3v)' equal to zero and attempt to solve: Simplifying 4 + -3v = 0 Solving 4 + -3v = 0 Move all terms containing v to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -3v = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -3v = 0 + -4 -3v = 0 + -4 Combine like terms: 0 + -4 = -4 -3v = -4 Divide each side by '-3'. v = 1.333333333 Simplifying v = 1.333333333

Solution

v = {1, 1.333333333}

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